8x^2-80x+16=0

Solution for 8x^2-80x+16=0 equation:

8x^2-80x+16=0

a = 8; b = -80; c = +16;
Δ = b2-4ac
Δ = -802-4·8·16
Δ = 5888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5888}=\sqrt{256*23}=\sqrt{256}*\sqrt{23}=16\sqrt{23}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-16\sqrt{23}}{2*8}=\frac{80-16\sqrt{23}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+16\sqrt{23}}{2*8}=\frac{80+16\sqrt{23}}{16}
$